**1. How many pairs of letters are there in the word ‘CARROT’ which have as many letters between them in the word as in the alphabet ?**

A. 1

B. 2

C. 3

D. 4

Answer A

__Solution__
Letter in the word
C K E |
Letters in the alphabet
C D E |

**2.**

**How many pairs of letters in the word ‘BRIGHTER’ Have as many letters between them in the word as in the alphabet ?**

A. 1

B. 2

C. 3

D. 4

Answer C

__Solution__
Letter in the word
R O T |
Letters in the alphabet
R S T |

**3.**

**How many pairs of letters are there in the word ‘LANGUISH’ which have as many letters between them in the word as in the alphabet ?**

A. Nil

B. One

C. Two

D. None of these

Answer C

__Solution__
Letter in the word
Letters in the alphabet

__P__E__N____P__O__N____E__N__C____E__D__C__**4.**

**How many pairs of letters are there in the word ‘LANGUISH’ which have as many letters between them in the word as in the alphabet ?**

A. Nil

B. One

C. Two

D. Three

Answer C

__Solution__
Letter in the word
Letters in the alphabet

__L__A__N____L__M__N____U__I__S____U__T__S__**5.**

**How many paris of letters are there in the word ‘CLANGOUR’ which have as many letters between them in the word as in the alphabet ?**

A. One

B. two

C. Three

D. None of these

Answer D

__Solution__
Letter in the word
Letters in the
alphabet

L A N L M N

__C__L__A____C__B__A____C__L A N__G____C__D E F__G__L A N L M N

__L__A N G O U__R____L__M N O P Q__R____N__G O U__R____N__O P Q__R__**6.**

**A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?**

A. 10

B. 12

C. 14

D. 16

Answer C

__Solution__
Let number of
horses = number of men = x.

Then, number of
legs =

So, 5x = 70 or
x = 14.

**7.**

**A, B, C, D and E play a game of cards. A says to B, “If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has. A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?**

A. 28

B. 29

C. 31

D. 35

Answer A

__Solution__
Clearly, we have :

A = B - 3
..............(i)

D + 5 = E
...............(ii)

A + C = 2E
................(iii)

B + D = A + C = 2E
................(iv)

A + B + C + D + E = 150
...............(v)

From (iii), (ii)
and (v), we get : 5E = 150 or E = 30.

Putting E = 30 in
(ii), we get : D = 25.

Putting E = 30
and D = 25 in (iv), we get : B = 35.

Putting B = 35
in (i), we get : A = 32.

Putting A = 32
and E = 30 in (iii), we get : C = 28.

**8.**

**A, B, C, D and E play a game of cards. A says to B, “If you give me three cards you will have as many as E has and if I give you three cards, you will have and many as D has”. A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?**

A. 22

B. 23

C. 25

D. 35

Answer C

**9.**

**Robin says, If Jai gives me rs 40, he will have half as much as Atul, but i Atul gives me Rs 40, then the three of us will all have the same amount. What is the total amount of money that Robin, Jai and Atul have between them ?**

A. Rs 240

B. Rs 320

C. Rs 360

D. Rs 420

__Solution__
Clearly, we have :

..............(i)

A - 40 = J
...................(ii)

A - 40 = R + 40 .....................(iii)

Solving (i) and (ii) simultaneously, we get : J = 120 and A = 160.

Putting A = 160 in (iii), we get R = 80.

Total money = R + J + A = Rs. (80 + 120 + 160) =Rs. 360.

A - 40 = R + 40 .....................(iii)

Solving (i) and (ii) simultaneously, we get : J = 120 and A = 160.

Putting A = 160 in (iii), we get R = 80.

Total money = R + J + A = Rs. (80 + 120 + 160) =Rs. 360.

**10.**

**Mac has Rs. 3 more than Ken, but then Ken wins on the horses and trebles his money. So, that he now has Rs. 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken’s win ?**

A. Rs. 9

B. Rs. 11

C. Rs. 13

D. Rs. 15

Answer C

__Solution__Then, money with Mac = x + Rs. 3.

Now, 3x = (x+ x+ Rs. 3) + Rs. 2 or x = Rs. 5.

Total money with Mac and Ken = 2x = Rs. 13.

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