1. How many pairs of letters are there in the word ‘CARROT’ which
have as many letters between them in the word as in the alphabet ?
A. 1
B. 2
C. 3
D. 4
Answer A
Solution
Letter in the word
C K E
|
Letters in the alphabet
C D E
|
2. How many pairs of letters in the word
‘BRIGHTER’ Have as many letters between them in the word as in the alphabet ?
A. 1
B. 2
C. 3
D. 4
Answer C
Solution
Letter in the word
R O T
|
Letters in the alphabet
R S T
|
3. How many pairs of letters are there in the
word ‘LANGUISH’ which have as many letters between them in the word as in the
alphabet ?
A. Nil
B. One
C. Two
D. None of these
Answer C
Solution
Letter in the word
Letters in the alphabet
P E N P O N
E N C E D C
P E N P O N
E N C E D C
4. How many pairs of letters are there in the
word ‘LANGUISH’ which have as many letters between them in the word as in the
alphabet ?
A. Nil
B. One
C. Two
D. Three
Answer C
Solution
Letter in the word
Letters in the alphabet
L A N L M N
U I S U T S
L A N L M N
U I S U T S
5. How many paris of letters are there in the
word ‘CLANGOUR’ which have as many letters between them in the word as in the
alphabet ?
A. One
B. two
C. Three
D. None of these
Answer D
Solution
Letter in the word
Letters in the
alphabet
C L A C B A
C L A N G C D E F G
L A N L M N
L A N G O U R L M N O P Q R
N G O U R N O P Q R
C L A C B A
C L A N G C D E F G
L A N L M N
L A N G O U R L M N O P Q R
N G O U R N O P Q R
6. A certain number of horses and an equal
number of men are going somewhere. Half of the owners are on their horses back
while the remaining ones are walking along leading their horses. If the number
of legs walking on the ground is 70, how many horses are there ?
A. 10
B. 12
C. 14
D. 16
Answer C
Solution
Let number of
horses = number of men = x.
Then, number of
legs = 

So, 5x = 70 or
x = 14.
7. A, B, C, D and E play a game of cards. A
says to B, “If you give me 3 cards, you will have as many as I have at this
moment while if D takes 5 cards from you, he will have as many as E has. A and
C together have twice as many cards as E has. B and D together also have the
same number of cards as A and C taken together. If together they have 150
cards, how many cards has C got ?
A. 28
B. 29
C. 31
D. 35
Answer A
Solution
Clearly, we have :
A = B - 3
..............(i)
D + 5 = E
...............(ii)
A + C = 2E
................(iii)
B + D = A + C = 2E
................(iv)
A + B + C + D + E = 150
...............(v)
From (iii), (ii)
and (v), we get : 5E = 150 or E = 30.
Putting E = 30 in
(ii), we get : D = 25.
Putting E = 30
and D = 25 in (iv), we get : B = 35.
Putting B = 35
in (i), we get : A = 32.
Putting A = 32
and E = 30 in (iii), we get : C = 28.
8. A, B, C, D and E play a game of cards. A
says to B, “If you give me three cards you will have as many as E has and if I
give you three cards, you will have and many as D has”. A and B together have
10 cards more than what D and E together have. If B has two cards more than
what C has and the total number of cards be 133, how many cards does B have ?
A. 22
B. 23
C. 25
D. 35
Answer C
9. Robin says, If Jai gives me rs 40, he will
have half as much as Atul, but i Atul gives me Rs 40, then the three of us will
all have the same amount. What is the total amount of money that Robin, Jai and
Atul have between them ?
A. Rs 240
B. Rs 320
C. Rs 360
D. Rs 420
Solution
Clearly, we have :

A - 40 = J
...................(ii)
A - 40 = R + 40 .....................(iii)
Solving (i) and (ii) simultaneously, we get : J = 120 and A = 160.
Putting A = 160 in (iii), we get R = 80.
Total money = R + J + A = Rs. (80 + 120 + 160) =Rs. 360.
A - 40 = R + 40 .....................(iii)
Solving (i) and (ii) simultaneously, we get : J = 120 and A = 160.
Putting A = 160 in (iii), we get R = 80.
Total money = R + J + A = Rs. (80 + 120 + 160) =Rs. 360.
10. Mac has Rs. 3 more than Ken, but then Ken
wins on the horses and trebles his money. So, that he now has Rs. 2 more than
the original amount of money that the two boys had between them. How much money
did Mac and Ken have between them before Ken’s win ?
A. Rs. 9
B. Rs. 11
C. Rs. 13
D. Rs. 15
Answer C
Solution
Let
money with Ken = x.Then, money with Mac = x + Rs. 3.
Now, 3x = (x+ x+ Rs. 3) + Rs. 2 or x = Rs. 5.
Total money with Mac and Ken = 2x = Rs. 13.
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