# Logical Reasoning Questions and Answers with Solutions | Logical Reasoning Series - Part I |

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1. How many pairs of letters are there in the word ‘CARROT’ which have as many letters between them in the word as in the alphabet ?
A. 1
B. 2
C. 3
D. 4
Answer A
Solution
 Letter in the word C K E Letters in the alphabet C D E
2. How many pairs of letters in the word ‘BRIGHTER’ Have as many letters between them in the word as in the alphabet ?
A. 1
B. 2
C. 3
D. 4
Answer C
Solution
 Letter in the word R O T Letters in the alphabet R S T
3. How many pairs of letters are there in the word ‘LANGUISH’ which have as many letters between them in the word as in the alphabet ?
A. Nil
B. One
C. Two
D. None of these
Answer C
Solution
Letter in the word                                             Letters in the alphabet
P E N                                                                       P O N
E N C                                                                       E D C
4. How many pairs of letters are there in the word ‘LANGUISH’ which have as many letters between them in the word as in the alphabet ?
A. Nil
B. One
C. Two
D. Three
Answer C
Solution
Letter in the word                                                  Letters in the alphabet
L A N                                                                            L M N
U I S                                                                             U T S
5. How many paris of letters are there in the word ‘CLANGOUR’ which have as many letters between them in the word as in the alphabet ?
A. One
B. two
C. Three
D. None of these
Answer D
Solution
Letter in the word                                         Letters in the alphabet
C L A                                                                    C B A
C L A N G                                                           C D E F G
L A N                                                                    L M N
L A N G O U R                                                   L M N O P Q R
N G O U R                                                           N O P Q R
6. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
A. 10
B. 12
C. 14
D. 16
Answer C
Solution
Let  number of  horses = number of  men = x.
Then, number of  legs =
So, 5x = 70   or  x = 14.
7. A, B, C, D and E play a game of cards. A says to B, “If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has. A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?
A. 28
B. 29
C. 31
D. 35
Answer A
Solution
Clearly, we have :
A = B - 3             ..............(i)
D + 5 = E           ...............(ii)
A + C = 2E       ................(iii)
B + D = A + C = 2E    ................(iv)
A + B + C + D + E = 150    ...............(v)
From (iii), (ii)  and  (v), we get : 5E = 150 or E = 30.
Putting  E = 30 in (ii), we get : D = 25.
Putting  E = 30  and  D = 25 in  (iv), we  get :  B = 35.
Putting  B = 35  in (i), we  get : A = 32.
Putting  A = 32  and  E = 30 in (iii), we  get : C = 28.
8. A, B, C, D and E play a game of cards. A says to B, “If you give me three cards you will have as many as E has and if I give you three cards, you will have and many as D has”. A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?
A. 22
B. 23
C. 25
D. 35
Answer C

9. Robin says, If Jai gives me rs 40, he will have half as much as Atul, but i Atul gives me Rs 40, then the three of us will all have the same amount. What is the total amount of money that Robin, Jai and Atul have between them ?
A. Rs 240
B. Rs 320
C. Rs 360
D. Rs 420
Solution
Clearly, we have :
..............(i)
A - 40 = J             ...................(ii)
A - 40 = R + 40         .....................(iii)
Solving (i) and (ii) simultaneously, we get : J = 120 and A = 160.
Putting A = 160 in (iii), we get R = 80.
Total money = R + J + A = Rs. (80 + 120 + 160) =Rs. 360.
10. Mac has Rs. 3 more than Ken, but then Ken wins on the horses and trebles his money. So, that he now has Rs. 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken’s win ?
A. Rs. 9
B. Rs. 11
C. Rs. 13
D. Rs. 15
Answer C
Solution
Let  money with Ken = x.
Then, money with Mac = x + Rs. 3.
Now, 3x = (x+ x+ Rs. 3) + Rs. 2  or  x = Rs. 5.
Total  money  with  Mac  and  Ken = 2x = Rs. 13.